{"version":"1.0","provider_name":"Studijni-svet.cz","provider_url":"https:\/\/studijni-svet.cz\/kurzy","author_name":"Studijni-svet.cz","author_url":"https:\/\/studijni-svet.cz\/kurzy\/author\/admin\/","title":"Objem kruhu - p\u0159\u00edklad 1 | Studijni-svet.cz","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"XtcOTWit7O\"><a href=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/objem-kruhu-priklad-1\/\">Objem kruhu &#8211; p\u0159\u00edklad 1<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/objem-kruhu-priklad-1\/embed\/#?secret=XtcOTWit7O\" width=\"600\" height=\"338\" title=\"&#8222;Objem kruhu &#8211; p\u0159\u00edklad 1&#8220; &#8212; Studijni-svet.cz\" data-secret=\"XtcOTWit7O\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/studijni-svet.cz\/kurzy\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"Zad\u00e1n\u00ed: Obd\u00e9ln\u00edk ABCD m\u00e1 n\u00e1sleduj\u00edc\u00ed vrcholy: A [-3; -1], B [-2; -1], C [2; 1], D [1; 3]. K obd\u00e9ln\u00edku je opsan\u00e1 kru\u017enice k. Jak\u00fd je obsah kruhu ohrani\u010den\u00e9ho kru\u017enic\u00ed k?$$a) 25 \u03c0$$$$b) frac{94}{5}\u03c0$$$$c) frac{25}{2}\u03c0$$$$d) 5 \u03c0$$$$e) frac{25}{4}\u03c0$$ \u0158e\u0161en\u00ed: St\u0159ed opsan\u00e9 kru\u017enice je v pr\u016fse\u010d\u00edku \u00fahlop\u0159\u00ed\u010dek obd\u00e9ln\u00edku ABCD. Pr\u016fse\u010d\u00edk je v polovin\u011b \u00fahlop\u0159\u00ed\u010dek AC i ... Read more","thumbnail_url":"https:\/\/studijni-svet.cz\/kurzy\/wp-content\/uploads\/2022\/09\/kruh-300x278.png"}