{"version":"1.0","provider_name":"Studijni-svet.cz","provider_url":"https:\/\/studijni-svet.cz\/kurzy","author_name":"Studijni-svet.cz","author_url":"https:\/\/studijni-svet.cz\/kurzy\/author\/admin\/","title":"\u0158e\u0161en\u00fd p\u0159\u00edklad 1 | Studijni-svet.cz","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"Ceg0zzotfw\"><a href=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/reseny-priklad-1-3\/\">\u0158e\u0161en\u00fd p\u0159\u00edklad 1<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/reseny-priklad-1-3\/embed\/#?secret=Ceg0zzotfw\" width=\"600\" height=\"338\" title=\"&#8222;\u0158e\u0161en\u00fd p\u0159\u00edklad 1&#8220; &#8212; Studijni-svet.cz\" data-secret=\"Ceg0zzotfw\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/studijni-svet.cz\/kurzy\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"Zad\u00e1n\u00ed: \u0158e\u0161te s pomoc\u00ed substituce rovnici (v mno\u017ein\u011b R). $${({x}^{2}-x+2)}^{2}-6({x}^{2}-x)-4=0$$ \u0158e\u0161en\u00ed: $${({x}^{2}-x+2)}^{2}-6({x}^{2}-x)-4=0$$ v obou z\u00e1vork\u00e1ch se vyskytuje \u010dlen x\u00b2-x, budeme tedy substituovat ten $${x}^{2}-x=a$$ $${(a+2)}^{2}-6a-4=0$$ $${a}^{2}+4a+4-6a-4=0$$ $${a}^{2}-2a=0$$ S pou\u017eit\u00edm Vietov\u00fdch vzorc\u016f najdeme ko\u0159eny rovnice ax\u00b2+bx+c=0 (x1+x2=-b; x1\u00b7x2=c) a1+a2=-b ; a1\u2022 a2=c a1+a2=2 a1\u2022a2=0 a1=2; a2=0 Nyn\u00ed se m\u016f\u017eeme vr\u00e1tit ke vztahu: $${x}^{2}-x=a$$ a naj\u00edt \u0159e\u0161en\u00ed ... Read more"}