{"version":"1.0","provider_name":"Studijni-svet.cz","provider_url":"https:\/\/studijni-svet.cz\/kurzy","author_name":"Studijni-svet.cz","author_url":"https:\/\/studijni-svet.cz\/kurzy\/author\/admin\/","title":"\u0158e\u0161en\u00fd p\u0159\u00edklad 2 | Studijni-svet.cz","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"kAJnnOHJQr\"><a href=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/reseny-priklad-2-2\/\">\u0158e\u0161en\u00fd p\u0159\u00edklad 2<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/reseny-priklad-2-2\/embed\/#?secret=kAJnnOHJQr\" width=\"600\" height=\"338\" title=\"&#8222;\u0158e\u0161en\u00fd p\u0159\u00edklad 2&#8220; &#8212; Studijni-svet.cz\" data-secret=\"kAJnnOHJQr\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/studijni-svet.cz\/kurzy\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"Zad\u00e1n\u00ed: \u0158e\u0161te rovnici (v mno\u017ein\u011b R): $$frac{{x}^{2}-4}{{x}^{2}-x-6}-frac{3}{2}=0$$ \u0158e\u0161en\u00ed: Za\u010dneme t\u00edm, \u017ee si \u010ditatel uprav\u00edme podle vzorce a\u00b2-b\u00b2=(a+b)(a-b), jmenovatel podle Vietov\u00fdch vzorc\u016f ax\u00b2+bx+c=0 (x1+x2=-b; x1\u00b7x2=c) a zlomek bez x p\u0159esuneme na pravou stranu. Dostaneme: $$frac{(x+2)(x-2)}{(x+2)(x-3)}=frac{3}{2}$$ V tuto chv\u00edli si stanov\u00edme podm\u00ednky pro x, kter\u00e9 budou n\u00e1sleduj\u00edc\u00ed: x\u2260-2 a x\u22603, jinak by ve jmenovateli byla nula. Z\u00e1rove\u0148 ... Read more"}