{"version":"1.0","provider_name":"Studijni-svet.cz","provider_url":"https:\/\/studijni-svet.cz\/kurzy","author_name":"Studijni-svet.cz","author_url":"https:\/\/studijni-svet.cz\/kurzy\/author\/admin\/","title":"Zlomky - p\u0159\u00edklad 1 | Studijni-svet.cz","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"Fgh3M1fskQ\"><a href=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/zlomky-priklad-1\/\">Zlomky &#8211; p\u0159\u00edklad 1<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/zlomky-priklad-1\/embed\/#?secret=Fgh3M1fskQ\" width=\"600\" height=\"338\" title=\"&#8222;Zlomky &#8211; p\u0159\u00edklad 1&#8220; &#8212; Studijni-svet.cz\" data-secret=\"Fgh3M1fskQ\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/studijni-svet.cz\/kurzy\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"Zad\u00e1n\u00ed: $$2(3-frac{n}{2}-frac{n}{2})(3+frac{n}{2}+frac{n}{2})=$$Odstra\u0148te z\u00e1vorky a zjednodu\u0161te (n&nbsp;\u2208 N). \u0158e\u0161en\u00ed: 1) \u010c\u00edslo 3 v obou z\u00e1vork\u00e1ch uprav\u00edme na zlomek, tak aby v\u0161e bylo sou\u010d\u00e1st\u00ed$$2(frac{6-n-n}{2})(frac{6+n+n}{2})$$2) Se\u010dteme n$$2(frac{6-2n}{2})(frac{6+2n}{2})$$3) Vytkneme dvojku$$2(frac{2(3-n}{2})(frac{2(3+n)}{2})$$4) D\u00edky tomu se n\u00e1m dvojky vykr\u00e1t\u00ed a m\u00e1me \u010d\u00edsla beze zlomku$$2(3-n)(3+n)$$5) Nyn\u00ed rozn\u00e1sob\u00edme z\u00e1vorky, abychom m\u011bli jen jednu$$2(9-n^{2})$$6) V posledn\u00edm kroku se zbav\u00edme z\u00e1vorky, rozn\u00e1sob\u00edme$$ 18-2n^{2}$$ \u010casov\u00e1 n\u00e1ro\u010dnost: 4 ... Read more"}