{"id":2432,"date":"2022-04-23T08:07:07","date_gmt":"2022-04-23T08:07:07","guid":{"rendered":"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/kombinatoricke-pravidlo-soucinu-vzorce\/"},"modified":"2022-05-01T21:46:20","modified_gmt":"2022-05-01T19:46:20","slug":"kombinatoricke-pravidlo-soucinu-vzorce","status":"publish","type":"lesson","link":"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/kombinatoricke-pravidlo-soucinu-vzorce\/","title":{"rendered":"Kombinatorick\u00e9 pravidlo sou\u010dinu vzorce"},"content":{"rendered":"<p>V kombinatorice se vyu\u017e\u00edvaj\u00ed dv\u011b z\u00e1kladn\u00ed pravidla:<\/p>\n<ul>\n<li>kombinatorick\u00e9 pravidlo sou\u010dinu<\/li>\n<li>kombinatorick\u00e9 pravidlo sou\u010dtu.<\/li>\n<\/ul>\n<p>Poj\u010fme si nejprve vysv\u011btlit KOMBINATORICK\u00c9 PRAVIDLO SOU\u010cINU.<\/p>\n<ul>\n<li>Definice zn\u00ed n\u00e1sledovn\u011b: Po\u010det v\u0161ech uspo\u0159\u00e1dan\u00fdch k-tic, jejich\u017e prvn\u00ed \u010dlen lze vybrat n1 zp\u016fsoby, druh\u00fd \u010dlen po v\u00fdb\u011bru prvn\u00edho \u010dlenu n2 zp\u016fsoby atd. a\u017e k-t\u00fd \u010dlen po v\u00fdb\u011bru v\u0161ech p\u0159edch\u00e1zej\u00edc\u00edch \u010dlen\u016f nk zp\u016fsoby, je roven<em><strong> n1\u22c5 n2\u22c5 \u2026 \u22c5 nk.<\/strong><\/em><\/li>\n<li>V praxi to znamen\u00e1, \u017ee mezi sebou n\u00e1sob\u00edme zp\u016fsoby, kter\u00fdmi je mo\u017en\u00e9 zvolit ur\u010dit\u00e9 k-tice.<\/li>\n<\/ul>\n<p>Vzorov\u00fd p\u0159\u00edklad:<\/p>\n<p>M\u00e1me k dispozici 3 r\u016fzn\u00e1 tri\u010dka a 5 r\u016fzn\u00fdch \u0161\u00e1tk\u016f<br \/>\nKolika zp\u016fsoby si m\u016f\u017eeme vz\u00edt tri\u010dko a \u0161\u00e1tek, abychom poka\u017ed\u00e9 vypadali jinak?<\/p>\n<p><strong>\u0158e\u0161en\u00ed:<\/strong><\/p>\n<p>Tri\u010dka si m\u016f\u017eeme vybrat t\u0159emi zp\u016fsoby (proto\u017ee m\u00e1me na v\u00fdb\u011br t\u0159i mo\u017enosti)<\/p>\n<p>Sukni si m\u016f\u017eeme vybrat p\u011bti zp\u016fsoby (proto\u017ee vol\u00edme z p\u011bti mo\u017enost\u00ed)<\/p>\n<p>To znamen\u00e1, \u017ee <em><strong>n1=3<\/strong><\/em> a <em><strong>n2=5<\/strong><\/em> \u21d2 <em><strong>n1\u22c5 n2 = 3x 5 = 15\u00a0<\/strong><\/em><\/p>\n<p>M\u00e1me 15 r\u016fzn\u00fdch zp\u016fsob\u016f jak zkombinovat jedno ze 3 tri\u010dek a jeden z 5 \u0161\u00e1tk\u016f.<\/p>\n","protected":false},"comment_status":"closed","ping_status":"closed","template":"","class_list":["post-2432","lesson","type-lesson","status-publish","hentry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Kombinatorick\u00e9 pravidlo sou\u010dinu vzorce | Studijni-svet.cz<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/studijni-svet.cz\/kurzy\/courses\/matematika-k-maturite\/lekce\/kombinatoricke-pravidlo-soucinu-vzorce\/\" \/>\n<meta property=\"og:locale\" content=\"cs_CZ\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Kombinatorick\u00e9 pravidlo sou\u010dinu vzorce | Studijni-svet.cz\" \/>\n<meta property=\"og:description\" content=\"V kombinatorice se vyu\u017e\u00edvaj\u00ed dv\u011b z\u00e1kladn\u00ed pravidla: kombinatorick\u00e9 pravidlo sou\u010dinu kombinatorick\u00e9 pravidlo sou\u010dtu. Poj\u010fme si nejprve vysv\u011btlit KOMBINATORICK\u00c9 PRAVIDLO SOU\u010cINU. Definice zn\u00ed n\u00e1sledovn\u011b: Po\u010det v\u0161ech uspo\u0159\u00e1dan\u00fdch k-tic, jejich\u017e prvn\u00ed \u010dlen lze vybrat n1 zp\u016fsoby, druh\u00fd \u010dlen po v\u00fdb\u011bru prvn\u00edho \u010dlenu n2 zp\u016fsoby atd. a\u017e k-t\u00fd \u010dlen po v\u00fdb\u011bru v\u0161ech p\u0159edch\u00e1zej\u00edc\u00edch \u010dlen\u016f nk zp\u016fsoby, je roven ... 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Poj\u010fme si nejprve vysv\u011btlit KOMBINATORICK\u00c9 PRAVIDLO SOU\u010cINU. Definice zn\u00ed n\u00e1sledovn\u011b: Po\u010det v\u0161ech uspo\u0159\u00e1dan\u00fdch k-tic, jejich\u017e prvn\u00ed \u010dlen lze vybrat n1 zp\u016fsoby, druh\u00fd \u010dlen po v\u00fdb\u011bru prvn\u00edho \u010dlenu n2 zp\u016fsoby atd. a\u017e k-t\u00fd \u010dlen po v\u00fdb\u011bru v\u0161ech p\u0159edch\u00e1zej\u00edc\u00edch \u010dlen\u016f nk zp\u016fsoby, je roven ... 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